Question Detail
Question
Heating 15.0 g of water from 20.0°C to 50.0°C requires __________ kJ of heat.
Correct Answer
Option A is the correct answer.
Detailed Explanation
q = m * c * ΔT = 15.0 g * 4.184 J/g°C * 30.0°C = 1882.8 J = 1.88 kJ.
Hint
Use the specific heat of water (4.184 J/g°C).