Question Detail
Question
Find the sum of the first 46 terms of the geometric progression 1/2, 1/4, 1/8, ...
Correct Answer
Option A is the correct answer.
Detailed Explanation
a=1/2, r=1/2. S_n = a(1−r^n)/(1−r) = (1/2)(1−(1/2)^46)/(1/2) = 1−(1/2)^46 ≈ 1 for large n.
Hint
Use GP sum formula S_n = a(1−r^n)/(1−r) for r<1.