Question Detail
Question
Find the sum of the first 75 terms of the arithmetic progression 2, 5, 8, ...
Correct Answer
Option A is the correct answer.
Detailed Explanation
a=2, d=3, n=75; S_n = n/2[2a + (n−1)d] = 75/2[4 + 222] = 75/2×226=37.5×226=8475.
Hint
Use S_n = n/2[2a + (n−1)d].