Question Detail
Question
Find the 10th term of an AP whose sum of first 10 terms is 200 and first term is 8.
Correct Answer
Option A is the correct answer.
Detailed Explanation
S_10 = 10/2[2a + 9d] = 200 → 5[16+9d]=200 → 16+9d=40 → 9d=24 → d=8/3≈2.667. t_10=a+9d=8+9×(8/3)=8+24=32.
Hint
First find d from sum formula, then t_n.