Question Detail
Question
A 2.8 g bullet traveling at 540 m/s enters a wall and exits with a speed of 120 m/s. What is the amount of energy transferred?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The kinetic energy lost by the bullet is transferred. Initial KE = 1/2 * 0.0028 kg * (540 m/s)^2. Final KE = 1/2 * 0.0028 kg * (120 m/s)^2. The difference is approximately 388 J.
Hint
Calculate the change in kinetic energy using KE = 1/2 mv^2.