Question Detail

PHY 101 PHY 101 Past Questions Objective Question
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Question

A uniform meter rule weighs 1 kg and is pivoted at 60 cm. A 40 g mass hangs at 100 cm. At which mark should a 30 g mass be placed for equilibrium?
Options
A 20 cm
B 30 cm
Correct Answer
C 40 cm
D 50 cm
Correct Answer

Option B is the correct answer.

Detailed Explanation

Moments about pivot: rule weight (1000 g) acts at 50 cm → 10 cm left. 1000×10 = 10000 g·cm. 40 g at 40 cm right → 1600. Balance: 30×x = 11600 → x ≈ 30 cm.

Hint

Sum moments about pivot.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 174 of 1250
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