Question Detail
Question
3200 J of heat is added to a system, and 1500 J of work is done on the system. What is the change in internal energy of the system?
Correct Answer
Option D is the correct answer.
Detailed Explanation
Change in internal energy ΔU = Q + W = 3200 J + 1500 J = 4700 J.
Hint
First law of thermodynamics: ΔU = Q + W, where W is work done on the system.