Question Detail
Question
What is the acceleration due to gravity on the surface of the moon if the mass of the moon is 1/80 that of Earth and its radius is one-fourth that of Earth?
Correct Answer
Option B is the correct answer.
Detailed Explanation
g_moon = G(M_earth/80) / (R_earth/4)^2 = GM_earth/(80) * (16/R_earth^2) = (16/80) * (G M_earth/R_earth^2) = (1/5) g_earth. So g_moon = GMe/(5Re^2).
Hint
Use g = GM/R^2 and substitute given fractions.