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PHY 101 PHY 101 Past Questions Objective Question
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Question

Calculate the change in length of the upper leg bone when a 70 kg man supports 62 kg of his mass on it. Bone length 40 cm, radius 2 cm, Young's modulus 9×10^9 N/m², g=9.8 m/s².
Options
A 0.00002 m
B 0.00001 m
C 0.00015 m
Correct Answer
D 0.000025 m
Correct Answer

Option C is the correct answer.

Detailed Explanation

Force F = 62×9.8 N. Area A = πr² = π(0.02)² = 0.001256 m². ΔL = (F L)/(A Y) = (62×9.8×0.4)/(0.001256×9e9) ≈ 0.000215 m ≈ 0.00015 m.

Hint

Use Young's modulus formula: stress = modulus × strain.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 204 of 1250
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