Question Detail
Question
A grindstone rotates with constant angular acceleration α = 0.35 rad/s². At time t = 0 it has angular velocity ω₀ = 4.6 rad/s and angular position θ₀ = 0. At what time will the reference line reach θ = 5.0 revolutions?
Correct Answer
Option A is the correct answer.
Detailed Explanation
5 revolutions = 10π = 31.42 rad. Using θ = ω₀t + ½αt² → 31.42 = 4.6t + 0.175t². Solving gives t ≈ 23 s.
Hint
Use rotational kinematics: θ = ω₀t + ½αt².