Question Detail
Question
How much heat input is needed to raise the temperature of a 20 kg iron vat filled with 3 kg of water from 10°C to 90°C? (c_iron = 450 J/kg°C, c_water = 4186 J/kg°C)
Correct Answer
Option A is the correct answer.
Detailed Explanation
Total heat = m₁c₁ΔT + m₂c₂ΔT = (20×450×80) + (3×4186×80) ≈ 1.72×10⁶ J = 1.72 MJ.
Hint
Heat gained by container + heat gained by water.