Question Detail
Question
257.8 mL of 0.0468 M Pb(NO₃)₂ is mixed with 156.00 mL of 0.095 M Na₂S. What mass of PbS precipitate forms?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Lead nitrate provides the limiting ions. Multiplying limiting moles by molar mass of PbS gives about 2.89 g.
Hint
Moles = molarity × volume in liters.