Question Detail
Question
In an experiment, 0.886 moles of NO is mixed with 0.505 moles of O₂. Calculate the number of moles of NO₂ that can be produced. The balanced equation for the reaction is 2NO(g) + O₂(g) → 2NO₂(g)
Correct Answer
Option A is the correct answer.
Detailed Explanation
From the balanced equation, 2 moles of NO react with 1 mole of O₂ to produce 2 moles of NO₂. Calculate how much O₂ is needed for all 0.886 moles of NO: (1/2) × 0.886 = 0.443 mol O₂. Since 0.505 mol O₂ is available (more than 0.443 mol), NO is the limiting reagent. The moles of NO₂ produced are equal to the moles of NO reacted, which is 0.886 moles.
Hint
Determine which reactant is limiting by calculating how much of the other reactant is needed to react completely with it.