Question Detail
Question
You are provided with 1.00 mol of Mg and 0.252 mol of iron (III) oxide. The balanced equation for the reaction is 3Mg + Fe₂O₃ → 3MgO + 2Fe. [Mg = 24, Fe = 56]. What is the maximum amount of Fe that can be produced?
Correct Answer
Option A is the correct answer.
Detailed Explanation
From the previous question, Fe₂O₃ is the limiting reagent. The balanced equation shows 1 mol Fe₂O₃ produces 2 mol Fe. Therefore, moles of Fe produced = 2 × 0.252 mol = 0.504 mol. Molar mass of Fe = 56 g/mol. Mass of Fe = 0.504 mol × 56 g/mol = 28.224 g.
Hint
Use the limiting reagent to find the moles of Fe produced, then convert to grams using the molar mass.