Question Detail

CHM 101 Properties of Gases Objective Question
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Question

What is the mathematical expression for Gay-Lussac's Law?
Options
A P₁V₁ = P₂V₂
B V₁/T₁ = V₂/T₂
C P₁/T₁ = P₂/T₂
Correct Answer
D Rate₁/Rate₂ = √(M₂/M₁)
Correct Answer

Option C is the correct answer.

Detailed Explanation

Gay-Lussac's Law is mathematically expressed as P₁/T₁ = P₂/T₂.

Hint

The notes provide this equation.

Question Info

Course: CHM 101
Topic: Properties of Gases
Type: Objective
Difficulty: Not specified
Question 703 of 1872
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