Question Detail
Question
In the reaction 4HCl(aq) + MnO₂(s) → Cl₂(g) + 2H₂O(l) + MnCl₂(aq), what amount of chlorine can be made from 5.2 mol of hydrochloric acid and 1.5 mol of manganese dioxide?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The balanced equation shows 4 mol HCl : 1 mol MnO₂. 5.2 mol HCl would require 1.3 mol MnO₂ (5.2/4). With 1.5 mol MnO₂ available, HCl is limiting. Amount of Cl₂ = 5.2 mol HCl × (1 mol Cl₂/4 mol HCl) = 1.3 mol.
Hint
The notes provide the answer as 1.3 mol.