Question Detail
Question
In the reaction of aluminum with iron(III) oxide, what amount of iron is expected when 0.26 mol of aluminum is combined with 0.10 mol of iron(III) oxide?
Correct Answer
Option B is the correct answer.
Detailed Explanation
The balanced equation is 2Al + Fe₂O₃ → 2Fe + Al₂O₃. 0.10 mol Fe₂O₃ requires 0.20 mol Al. With 0.26 mol Al available, Fe₂O₃ is limiting. Amount of Fe = 0.10 mol Fe₂O₃ × (2 mol Fe/1 mol Fe₂O₃) = 0.20 mol.
Hint
The notes provide the answer as 0.20 mol.