Question Detail
Question
If x² + y² + 4x - 6y + 13 = 0, what is the center of the circle?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Completing the square: (x² + 4x) + (y² - 6y) = -13. (x+2)² - 4 + (y-3)² - 9 = -13. (x+2)² + (y-3)² = 0. So center is (-2,3).
Hint
The notes indicate answer B.