Question Detail
Question
Given the parametric equations x - 9 = 3 cos θ and y + 14 = 3 sin θ, what is the centre of the circle?
Correct Answer
Option A is the correct answer.
Detailed Explanation
Rewriting: x = 9 + 3 cos θ and y = -14 + 3 sin θ. Comparing with the standard parametric form x = a + r cos θ, y = b + r sin θ, the centre (a, b) is (9, -14).
Hint
Rewrite the equations in the form x = a + r cos θ and y = b + r sin θ.