Question Detail
Question
In Example 4, what is the diver's speed as he hits the water?
Correct Answer
Option C is the correct answer.
Detailed Explanation
At the water surface, y_f = 0. Using energy conservation: mgy_i = ½mv_f², so v_f = √(2gy_i) = √(2×9.8×10) = √196 = 14 m/s.
Hint
All initial potential energy converts to kinetic energy.