Question Detail

PHY 101 Friction Objective Question
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Question

For the two-block system (6 kg on horizontal surface, μk=0.5, and a 4 kg hanging block), what is the equation of motion for the 6 kg block on the horizontal surface?
Options
A 40 - T = 6a
B T - μR = 6a
Correct Answer
C T - 40 = 6a
D μR - T = 6a
Correct Answer

Option B is the correct answer.

Detailed Explanation

The lecture shows the equation for the block on the horizontal surface as T - μR = 6a. Tension (T) pulls to the right, and kinetic friction (μR) opposes the motion to the left.

Hint

Apply Newton's second law to the 6 kg block. The direction of its acceleration (to the right) is positive. What are the horizontal forces acting on it?

Question Info

Course: PHY 101
Topic: Friction
Type: Objective
Difficulty: Not specified
Question 508 of 1250
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