Question Detail
Question
For the two-block system (6 kg block, μk=0.5, g=10 m/s²), what is the calculated acceleration of the blocks?
Correct Answer
Option C is the correct answer.
Detailed Explanation
From 40 - μR = 10a, with μR = 0.5 * 60 N = 30 N. So, 40 N - 30 N = 10a => 10 N = 10a => a = 1 m/s².
Hint
Substitute the value of the friction force (μR) into the combined equation 40 - μR = 10a and solve for a.