Question Detail
Question
In the equilibrium system with a 200 N block on a 30° frictionless incline and a hanging block, the tension T is found to be 100 N. What must be the weight (x) of the second block?
Correct Answer
Option B is the correct answer.
Detailed Explanation
The tension in the cord is also equal to the weight of the hanging block (assuming a massless, frictionless pulley). Therefore, the weight of the second block must be 100 N, which is equivalent to 10 kg.
Hint
For the hanging block in equilibrium, the upward tension must equal its downward weight.