Question Detail
Question
For the 120 N block on a 30° incline with μk=0.5, what is the component of its weight acting parallel to the incline?
Correct Answer
Option A is the correct answer.
Detailed Explanation
The parallel component is mg sin θ = 120 sin 30°. sin 30° = 0.5, so the force is 120 N * 0.5 = 60 N.
Hint
This is a direct calculation using the formula for the component of weight along the incline.