Question Detail

PHY 101 Mechanical Equilibrium and Rotational Dynamics Objective Question
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Question

A thin uniform rod is 1 m long and has a mass of 6 kg. It is pivoted at its centre and set into rotation with an angular velocity of 16 rad/s. Its angular momentum can be calculated using which formula and value of moment of inertia?
Options
A L = Iω, with I = (1/12)ml²
Correct Answer
B L = Iω, with I = (1/3)ml²
C L = mv r, with I = (1/12)ml²
D L = Iα, with I = (1/12)ml²
Correct Answer

Option A is the correct answer.

Detailed Explanation

Angular momentum L is calculated as L = Iω. For a thin rod pivoted about its centre, the appropriate moment of inertia formula is I = (1/12)ml². Therefore, L = [(1/12) × 6 kg × (1 m)²] × 16 rad/s.

Hint

First, identify the correct formula for the moment of inertia based on the axis location, then use it in the angular momentum equation.

Question Info

Course: PHY 101
Topic: Mechanical Equilibrium and Rotational Dynamics
Type: Objective
Difficulty: Not specified
Question 585 of 1250
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