Question Detail

PHY 101 Rigid Body Dynamics Objective Question

Question

The magnitude of the angular momentum L of a particle of mass m moving with velocity v at a position r from a reference point is given by L = m v r sin θ. What does the angle θ represent in this expression?
Options
A The angle between the velocity vector and the acceleration vector.
B The angle between the position vector r and the linear momentum vector p.
Correct Answer
C The angle between the radius of curvature and the tangent.
D The angle of rotation of the particle.
Correct Answer

Option B is the correct answer.

Detailed Explanation

The magnitude of a cross product A × B is |A||B| sin θ, where θ is the smaller angle between the vectors A and B. In the definition L = r × p, θ is the angle between the position vector r and the linear momentum vector p (which is in the direction of velocity v).

Hint

Consider the geometric meaning of the magnitude of a cross product.

Question Info