Question Detail
Question
A soap bubble has a radius of 2.0 × 10⁻⁴ m. Using a surface tension of 0.0370 N/m for soapy water, what is the gauge pressure inside the bubble?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The gauge pressure inside a soap bubble is given by P = 4γ / r. Substituting γ = 0.0370 N/m and r = 2.0 × 10⁻⁴ m gives P = (4 × 0.0370) / (2.0 × 10⁻⁴) = 0.148 / (2.0 × 10⁻⁴) = 740 N/m².
Hint
Use the correct formula for a soap bubble, which accounts for its two surfaces.