Question Detail
Question
A ball of mass 1.0 kg drops from a height of 2.5 m and rebounds to a height of 2.3 m. What is the energy lost during the collision with the ground?
Correct Answer
Option B is the correct answer.
Detailed Explanation
The energy lost is the difference in potential energy between the initial and final heights. ΔPE = mg(y₁ - y₂) = 1.0 kg × 9.8 m/s² × (2.5 m - 2.3 m) = 9.8 × 0.2 = 1.96 J. This energy is dissipated as heat and sound during the inelastic collision.
Hint
Energy lost equals the change in gravitational potential energy from the drop height to the rebound height.