Atomicity, Radicals & Valency — Key Chemistry Concepts
Topic Content
ATOMICITY, RADICALS & VALENCY
1️⃣ ATOMICITY
Definition
Atomicity is the number of atoms present in one molecule of a substance.
Example:
- O₂ = atomicity 2
- P₄ = atomicity 4
- S₈ = atomicity 8
ATOMICITY OF DIFFERENT CLASSES OF ELEMENTS
a. Noble gases → Monoatomic (Atomicity = 1)
Examples: He, Ne, Ar, Kr, Xe, Rn
These exist as single atoms because they have stable electron configurations.
b. Metals → Mostly Monoatomic
Examples: Na, K, Fe, Cu, Zn, Al, Mg
Metals exist as giant metallic lattices, but each particle is considered a single atom.
c. Non-metals → Mostly Diatomic (Atomicity = 2)
Examples:
- H₂, O₂, N₂
- Cl₂, Br₂, I₂
These exist naturally as pairs of atoms.
d. Triatomic Molecules (Atomicity = 3)
Examples:
- O₃ (ozone)
- CO₂ (carbon dioxide)
e. Tetra-atomic Molecules (Atomicity = 4)
Examples:
- P₄ (phosphorus)
- SO₃ (actually triatomic for the molecule SO₃, but the oxide ion in SO₃²⁻ has 4 atoms)
(Your list had a small mix-up, but P₄ is definitely tetra-atomic.)
f. Polyatomic Molecules (Atomicity > 4)
Examples:
- S₈ (sulphur)
- C₆H₁₂O₆ (glucose)
- C₁₂H₂₂O₁₁ (sucrose)
These contain many atoms.
2️⃣ RADICALS (Ions)
Definition
A radical (also called a polyatomic ion) is a group of atoms that carry a charge and behave like a single ion.
Examples:
|
Radical |
Formula |
Charge |
|
Hydroxide |
OH⁻ |
–1 |
|
Nitrate |
NO₃⁻ |
–1 |
|
Sulphate |
SO₄²⁻ |
–2 |
|
Carbonate |
CO₃²⁻ |
–2 |
|
Ammonium |
NH₄⁺ |
+1 |
Radicals do not exist freely in nature; they occur inside compounds.
3️⃣ VALENCY
Definition
Valency is the combining capacity of an element — how many electrons an atom can gain, lose, or share to form a stable compound.
Examples of valency
|
Element |
Valency |
|
H |
1 |
|
O |
2 |
|
N |
3 |
|
C |
4 |
|
Na |
1 |
|
Mg |
2 |
|
Al |
3 |
|
Cl |
1 |
|
S |
2 or 6 |
|
P |
3 or 5 |
Relationship with radicals
Radicals also have valencies which equal their charges.
|
Radical |
Charge |
Valency |
|
OH⁻ |
–1 |
1 |
|
SO₄²⁻ |
–2 |
2 |
|
CO₃²⁻ |
–2 |
2 |
✔ SUMMARY
- Atomicity → number of atoms in a molecule
- Radicals → charged groups of atoms behaving as a single ion
- Valency → combining power of an atom or radical
DETERMINING ATOMICITY
Atomicity means the number of atoms present in one molecule of a substance.
There are two main methods used to determine atomicity:
1️⃣ Counting the Number of Atoms in the Molecule
This is the simplest method.
- Simply look at the chemical formula and count how many atoms are present.
Examples:
- H₂ → atomicity = 2
- O₃ → atomicity = 3
- P₄ → atomicity = 4
- S₈ → atomicity = 8
2️⃣ Using the Ratio of Molecular Mass to Atomic Mass
(✨ This method is used only for molecules made of the same element, e.g., H₂, O₂, P₄, S₈.)
Formula:
Atomicity=Molecular MassAtomic Mass\text{Atomicity} = \frac{\text{Molecular Mass}}{\text{Atomic Mass}}Atomicity=Atomic MassMolecular Mass
Examples
a. Hydrogen molecule (H₂)
- Atomic mass of H = 1
- Molecular mass of H₂ = 2 × 1 = 2
Atomicity=21=2\text{Atomicity} = \frac{2}{1} = 2Atomicity=12=2
b. Oxygen molecule (O₂)
- Atomic mass of O = 16
- Molecular mass of O₂ = 2 × 16 = 32
Atomicity=3216=2\text{Atomicity} = \frac{32}{16} = 2Atomicity=1632=2
This ratio method only works for:
- Diatomic molecules (H₂, O₂, Cl₂, N₂)
- Polyatomic elements (P₄, S₈, O₃)
- Not for compounds (e.g., CO₂, H₂O)
✔ Quick Examples Using the Ratio Method
Sulphur (S₈)
- Atomic mass of S = 32
- Molecular mass = 8 × 32 = 256
25632=8⇒Atomicity = 8\frac{256}{32} = 8 \Rightarrow \text{Atomicity = 8}32256=8⇒Atomicity = 8
Phosphorus (P₄)
- Atomic mass of P = 31
- Molecular mass = 4 × 31 = 124
12431=4⇒Atomicity = 4\frac{124}{31} = 4 \Rightarrow \text{Atomicity = 4}31124=4⇒Atomicity = 4
✔ SUMMARY (Easy to Remember)
- Atomicity = number of atoms in a molecule.
- Can be found by:
- Counting atoms in the formula.
- Dividing molecular mass by atomic mass (only for elemental molecules).
✅ Atomicity Table (Corrected and Completed)
Atomicity = total number of atoms in one molecule of the substance.
1. Calcium carbonate
- Use: Limestone / Bones
- Formula: CaCO₃
- Atomicity: Ca(1) + C(1) + O₃(3) = 5
2. Aspirin (Acetylsalicylic acid)
Your formula had errors. Correct formula = C₉H₈O₄
- Use: Analgesic (pain relief)
- Formula: C₉H₈O₄
- Atomicity: 9 + 8 + 4 = 21
3. Iron(III) hydroxide
- Use: Cosmetics / Water treatment
- Formula: Fe(OH)₃
- Atomicity: Fe(1) + O₃(3) + H₃(3)
= 1 + 3 + 3 → 7
(You had 27 and 21, both incorrect.)
4. Paradichlorobenzene (PDCB)
Correct formula = C₆H₄Cl₂
- Use: Moth balls
- Formula: C₆H₄Cl₂
- Atomicity: 6 + 4 + 2 = 12
5. Magnesium hydroxide
- Use: Milk of magnesia
- Formula: Mg(OH)₂
- Atomicity: Mg(1) + O₂(2) + H₂(2)
= 1 + 2 + 2 → 5
6. TNT (Trinitrotoluene)
Formula: C₇H₅(NO₂)₃
- Use: Explosive
- Formula: C₇H₅(NO₂)₃
Atomicity: - C: 7
- H: 5
- (NO₂)₃ → N₃O₆ → total = 3 + 6 = 9
Total atomicity = 7 + 5 + 9 = 21
7. Pyrite
Formula: FeS₂
- Use: Fool’s gold
- Formula: FeS₂
- Atomicity: 1 + 2 = 3
8. Calcium dihydrogen phosphate
Formula: Ca(H₂PO₄)₂
- Use: Fertilizer
Atomicity: - Ca = 1
- (H₂PO₄)₂ →
- H = 4
- P = 2
- O = 8
Total = 1 + 4 + 2 + 8 = 15
9. Tetraoxosulphate(VI) acid (Sulphuric acid)
Correct formula = H₂SO₄
- Use: Fertilizer / Paper industry
- Formula: H₂SO₄
- Atomicity: 2 + 1 + 4 = 7
✅ FINAL CORRECTED TABLE
|
Substance |
Use |
Formula |
Atomicity |
|
Calcium carbonate |
Limestone/Bones |
CaCO₃ |
5 |
|
Aspirin |
Analgesic |
C₉H₈O₄ |
21 |
|
Iron(III) hydroxide |
Cosmetics/Water treatment |
Fe(OH)₃ |
7 |
|
Paradichlorobenzene |
Moth balls |
C₆H₄Cl₂ |
12 |
|
Magnesium hydroxide |
Milk of magnesia |
Mg(OH)₂ |
5 |
|
TNT |
Explosive |
C₇H₅(NO₂)₃ |
21 |
|
Pyrite |
Fool’s gold |
FeS₂ |
3 |
|
Calcium dihydrogen phosphate |
Fertilizer |
Ca(H₂PO₄)₂ |
15 |
|
Tetraoxosulphate(VI) acid |
Fertilizer/Paper industry |
H₂SO₄ |
7 |
175
Objective Questions