STA 112
PERMUTATIONS AND COMBINATIONS
Learn about PERMUTATIONS AND COMBINATIONS in STA 112. Comprehensive study materials and practice questions.
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STA 112Permutations and Combinations Study Summary
This document provides a comprehensive overview of Permutations and Combinations, including fundamental principles, definitions, formulas, important identities, and a set of practice questions with answers.
Key Concepts
Fundamental Principles of Counting
- Multiplication Principle: If an event can occur in 'm' different ways, followed by another event that can occur in 'n' different ways, then the total number of different ways of occurrence of the two events in order is m × n.
- Addition Principle: If there are two events such that they can occur independently in 'm' and 'n' different ways respectively, then either of the two events can occur in (m + n) ways.
Factorial
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Definition: The factorial of a natural number 'n', denoted by n! or ⌥n, is the continued product of the first 'n' natural numbers.
n! = n × (n - 1) × (n - 2) × ......... × 3 × 2 × 1
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Properties:
- n! = n × ((n - 1)!)
- n! = n × (n - 1) × ((n - 2)!)
Permutations
- Definition: A permutation is an arrangement of a number of objects in a definite order, taken some or all at a time.
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Number of Permutations of 'n' different objects taken 'r' at a time (without repetition):
nPr = P(n, r) = n! / (n-r)!
(where 0 ≤ r ≤ n)
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Number of Permutations of 'n' objects when repetition is allowed:
nr
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Number of Permutations of 'n' objects where p1 are of one kind, p2 are of second kind, ..., pk are of kth kind and the rest are different:
n! / (p1! p2! ... pk!)
Combinations
- Definition: A combination is a selection made by choosing some or all of a number of objects, without considering their order.
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Number of Combinations of 'n' objects taken 'r' at a time:
nCr = C(n, r) = n! / (r! (n-r)!)
(where 0 ≤ r ≤ n)
Important Identities and Results
- 0! = 1
- nC0 = nCn = 1
- nCr = nCn-r (where 0 ≤ r ≤ n, and r are positive integers)
- nPr = r! × nCr (where 0 ≤ r ≤ n, r and n are positive integers)
- nCr + nCr+1 = n+1Cr+1 (where 0 ≤ r ≤ n and r and N are positive integers)
- If nCa = nCb, then either a = b or a + b = n
Practice Questions
The document includes a variety of practice questions categorized by marks and type:
- Section A: Very Short Answer Type Questions (1 Mark)
- Section B: Short Answer Type Questions (2 Marks)
- Section C: Short Answer Type Questions (4 Marks)
- Section D: Long Answer Type Questions (6 Marks)
Answers
Detailed answers are provided for all the practice questions at the end of the document.