Question Detail
Question
The initial velocity of a particle moving along a straight line is 10 m/s and its retardation is 2 m/s². The distance moved by the particle in the fifth second of its motion is:
Correct Answer
Option A is the correct answer.
Detailed Explanation
Distance in nth second: s_n = u + ½a(2n-1). Here u = 10 m/s, a = -2 m/s² (retardation), n = 5. s_5 = 10 + ½(-2)(2×5-1) = 10 + (-1)(9) = 10 - 9 = 1 m.
Hint
s_n = u + ½a(2n-1).