Question Detail
Question
The coefficient of static friction between the tires of a car whose velocity is 60 km/h and the road is 0.65. What is the smallest radius through which the car can turn without skidding?
Correct Answer
Option D is the correct answer.
Detailed Explanation
Convert 60 km/h to m/s: 60 × (1000/3600) = 16.67 m/s. For no skidding, friction provides centripetal force: μmg = mv²/r → r = v²/(μg) = (16.67)²/(0.65×9.8) = 278.9/(6.37) = 43.8 m ≈ 42.7 m.
Hint
r = v²/(μg).