Question Detail

PHY 101 PHY 101 Past Questions Objective Question
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Question

A passenger in a lift experiences an upward normal force of 720 N. If the weight of the man is 690 N, find his acceleration.
Options
A 2.43 m/s²
B 1.32 m/s²
C 0.13 m/s²
D 0.43 m/s²
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

Net upward force = N - mg = ma. So 720 - 690 = (690/g)a. Assuming g=9.8, m=690/9.8=70.41 kg. Then 30 = 70.41a → a = 30/70.41 = 0.426 m/s² ≈ 0.43 m/s².

Hint

N - mg = ma.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1048 of 1250
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