Question Detail
Question
Two equal masses m at the ends of a mass-less thin bar of length l. Calculate the moment of inertia for an axis perpendicular to the bar through the centre.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Each mass is at distance l/2 from center. I = m(l/2)² + m(l/2)² = 2 × m × l²/4 = ml²/2.
Hint
I = Σmr².