Question Detail
Question
In an experiment 23.41g of HCl was reacted with 20.00 g of NaOH to give 26.54g of NaCl. The limiting reagent is
Correct Answer
Option A is the correct answer.
Detailed Explanation
Moles HCl = 23.41/36.46 = 0.642 mol. Moles NaOH = 20.00/40.00 = 0.500 mol. Reaction 1:1, so NaOH is the limiting reagent.
Hint
Calculate moles of each reactant and compare to the stoichiometric ratio.