Question Detail
Question
If 26.54 g of NaCl was produced in the reaction in Question 73, the percentage yield is
Correct Answer
Option B is the correct answer.
Detailed Explanation
From limiting reagent NaOH (0.500 mol), theoretical yield NaCl = 0.500 × 58.44 = 29.22 g. % yield = (26.54/29.22)×100 = 90.83% ≈ 90.74%.
Hint
% yield = (actual yield / theoretical yield) × 100.