Question Detail
Question
How many moles of ammonium ions are in 8.776 g of ammonium carbonate (NH₄)₂CO₃? [N=14; H=1; C=12; O=16]
Correct Answer
Option C is the correct answer.
Detailed Explanation
Molar mass (NH₄)₂CO₃ = (2×18) + 12 + 48 = 36+12+48=96 g/mol. Moles compound = 8.776/96 = 0.0914 mol. Each formula unit contains 2 NH₄⁺ ions, so moles NH₄⁺ = 0.0914 × 2 = 0.1828 ≈ 0.18 mol.
Hint
Multiply moles of compound by the number of ammonium ions per formula unit.