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CHM 101 CHM 101 Past Questions Objective Question
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Question

A compound has the following composition 48.64% carbon, 8.16% hydrogen, and 43.20% oxygen. Determine the empirical formula of the compound
Options
A CHO₂
B C₃H₆O₂
Correct Answer
C CH₂O
D C₆H₁₂O₄
Correct Answer

Option B is the correct answer.

Detailed Explanation

Assume 100 g: C = 48.64/12 = 4.053, H = 8.16/1 = 8.16, O = 43.20/16 = 2.70. Divide by smallest (2.70): C = 1.5, H = 3.02, O = 1. Multiply by 2: C₃H₆O₂.

Hint

Convert percentages to moles, divide by smallest, multiply to get whole numbers.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1101 of 1872
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