Question Detail
Question
What is the mass percent composition of fluorine in haloethane (C₂HBrClF₃)?
Correct Answer
Option A is the correct answer.
Detailed Explanation
Molar mass = (2×12.01) + (1×1.008) + (1×79.90) + (1×35.45) + (3×19.00) = 24.02 + 1.008 + 79.90 + 35.45 + 57.00 = 197.378 g/mol. Mass of F = 57.00 g/mol. %F = (57.00/197.378)×100 = 28.88% ≈ 28.86%.
Hint
Calculate total molar mass first, then (mass of all fluorine atoms / total mass) × 100%.