Question Detail

CHM 101 CHM 101 Past Questions Objective Question
Take CBT

Question

How many moles are present in 3.01 × 10²³ molecules of water?
Options
A 0.25 mol
B 0.50 mol
Correct Answer
C 1.00 mol
D 2.00 mol
Correct Answer

Option B is the correct answer.

Detailed Explanation

Avogadro's number = 6.022 × 10²³ molecules/mol. Moles = (3.01 × 10²³) / (6.022 × 10²³) = 0.50 mol.

Hint

Moles = number of particles / Avogadro's number.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1364 of 1872
Previous Course Details Next