Question Detail
Question
For the reaction 2A + B → C, the rate law is rate = k[A]²[B]. If the concentration of A is doubled and the concentration of B is halved, the rate will change by a factor of:
Correct Answer
Option A is the correct answer.
Detailed Explanation
Initial rate = k[A]²[B]. New rate = k[2A]²[½B] = k × 4 × ½ × [A]²[B] = 2 × k[A]²[B]. Factor = 2.
Hint
The factor for A² is 2² = 4, for B is ½; overall factor = 4 × ½ = 2.