Question Detail
Question
The expansion of \( (1 + y)^{-1} \) is:
Correct Answer
Option A is the correct answer.
Detailed Explanation
(1+y)^(-1) = 1/(1+y) = 1 - y + y² - y³ + ... = Σ (-1)^p y^p for |y|<1.
Hint
Recall the geometric series: 1/(1+y) = Σ (-1)^n y^n for |y|<1.