Question Detail
Question
If i is a root of the quadratic equation \( x^2 - mx + 1 = 0 \), then the value of m is:
Correct Answer
Option A is the correct answer.
Detailed Explanation
If i is a root, then its complex conjugate -i is also a root. Sum of roots = i + (-i) = 0 = m. So m = 0. Alternatively, substitute x=i: i² - m i + 1 = -1 - m i + 1 = -m i = 0 => m=0.
Hint
For a quadratic with real coefficients, complex roots occur in conjugate pairs.