Question Detail
Question
What is the limit of \( \frac{x^3 - 6x + 2}{x^2 + x + 9} \) as \( x \) approaches 2?
Correct Answer
Option B is the correct answer.
Detailed Explanation
By direct substitution: ( \frac{2^3 - 6(2) + 2}{2^2 + 2 + 9} = \frac{8 - 12 + 2}{4 + 2 + 9} = \frac{-2}{15} ).
Hint
Exercise 1.1, Question 1.