Question Detail
Question
Evaluate the limit of \( \frac{(x-2)^3 + 8}{x} \) as \( x \) approaches 0.
Correct Answer
Option C is the correct answer.
Detailed Explanation
Expand ( (x-2)^3 + 8 ) to get ( x^3 - 6x^2 + 12x ). Dividing by ( x ) leaves ( x^2 - 6x + 12 ). At ( x=0 ), this is 12.
Hint
Exercise 1.1, Question 2.