Question Detail
Question
Evaluate the limit of \( \frac{e^x - 1}{\tan 2x} \) as \( x \) tends to 0.
Correct Answer
Option C is the correct answer.
Detailed Explanation
Using L'Hospital's rule: ( \frac{e^x}{2 \sec^2 2x} ). At ( x=0 ), this is ( \frac{1}{2 \cdot 1} = \frac{1}{2} ).
Hint
Exercise 1.1, Question 36.