Question Detail
Question
Evaluate the limit of \( \frac{\cos x - 1}{\cos 2x - 1} \) as \( x \) tends to 0.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Using L'Hospital's rule twice, the result is ( \frac{1^2}{2^2} = \frac{1}{4} ).
Hint
Exercise 1.1, Question 37.