Question Detail
Question
metal ball of 10 kg with 5 C charge moves perpendicular to magnetic field of 5 T. Radius of path is 80 m. Speed and period?
Correct Answer
Option D is the correct answer.
Detailed Explanation
r = mv/(qB) → v = (rqB)/m = (80×5×5)/10 = 2000/10 = 200 m/s. T = 2πr/v = 2π×80/200 = (160π)/200 = 0.8π ≈ 2.51 s ≈ 2.5 s.
Hint
v = rqB/m, T = 2πr/v.