Question Detail
Question
The power dissipated by a 72 Ω resistor connected to sinusoidal AC source is 24 W. Peak-to-peak voltage?
Correct Answer
Option A is the correct answer.
Detailed Explanation
P = V_rms²/R → V_rms = √(P×R) = √(24×72) = √1728 = 41.57 V. V_peak = V_rms × √2 = 41.57×1.414 = 58.8 V. V_pp = 2×V_peak = 117.6 V ≈ 117.5 V.
Hint
V_pp = 2√2 × V_rms.