Question Detail

PHY 102 Coulomb's law and Electric Fields Objective Question
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Question

In Solved Problem 25.1, the potential difference between two metal plates in air is 40 V, and the plate separation is 5.0 mm. What is the magnitude of the electric field E between the plates?
Options
A 0.50 kV/m
B 8.0 kV/m
Correct Answer
C 200 kV/m
D 0.12 kV/m
Correct Answer

Option B is the correct answer.

Detailed Explanation

From Solved Problem 25.1(d): E = V/d = 40 V / 0.0050 m = 8000 V/m = 8.0 kV/m.

Hint

Remember the relationship between electric field, potential difference, and distance for parallel plates: E = V/d. Convert units to be consistent.

Question Info

Course: PHY 102
Topic: Coulomb's law and Electric Fields
Type: Objective
Difficulty: Not specified
Question 885 of 1819
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